Comments on: Hibernate HQL like query using named parameters

By: Kuu

Kuu — Mon, 06 Feb 2012 12:08:58 +0000

Thanks, you saved me the day

ctrejos1284 — Thu, 28 Apr 2011 19:46:33 +0000

you can also do it without the findByNamedParam… try it in this way:

dbquery = “u from user u where u.name like ‘%”+ str +”%’”;
List l= getHibernateTemplate().find(dbquery);

Nitish N — Mon, 24 Jan 2011 20:14:41 +0000

String query = “from user u where u.name like :name”

getHibernateTemplate().findByNamedParam(query, “name”, ‘%’ + str + ‘%’);

this helped me…..thanks for that…. but this is case sensitivity, and i want to search irrespective of case.

voyage — Wed, 05 Jan 2011 03:11:09 +0000

ActiveRecord HQL LIKE query with parameters | DJ Schwartz — Sat, 07 Aug 2010 04:37:27 +0000

[...] a little help from Stefan Pettersson’s blog I found my solution, add the percent signs inside the [...]

ActiveRecord HQL LIKE query with parameters « Dan Schwartz — Wed, 30 Jun 2010 20:26:43 +0000

[...] a little help from Stefan Pettersson’s blog I found my solution, add the percent signs inside the [...]

Manish — Fri, 11 Jun 2010 07:40:01 +0000

Thanks a lot it works!!

sam — Wed, 05 May 2010 19:46:34 +0000

session.createQuery(“from Entity where property like :prefix”).setString(“prefix”,myString.concat(“%”)).list();

solved my problem, but actually i was searching for a better solution …
looks quite dirty to me.

Aditya — Wed, 14 Apr 2010 20:10:48 +0000

Thanks Stefan….

Diederick — Thu, 28 Jan 2010 10:20:31 +0000

Excellent. Works with TopLink Essentials as well.